思路:① 找初始左边界:第一个 nums[i] nums[i+1];② 找初始右边界:最后一个 nums[i] < nums[i-1];③ 求 [left,right] 内 min、max;④ 向左扩展:nums[left-1] minVal 则 left--;⑤ 向右扩展:nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
Маргарита Щигарева。关于这个话题,服务器推荐提供了深入分析
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将 Node.js 添加到 PATH:
But that’s a lot of resetting! We can save a bunch of bandwidth by instead tracking the current foreground and background color in our renderer and only emitting a new color escape sequence when our desired color changes. This is an annoying amount of bookkeeping but it substantially cuts down on the amount of escape codes emitted.